1/4(x^2-10x+17)=0

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Solution for 1/4(x^2-10x+17)=0 equation: 


x in (-oo:+oo)

(1/4)*(x^2-(10*x)+17) = 0

(1/4)*(x^2-10*x+17) = 0

1/4*(x^2-10*x+17) = 0

x^2-10*x+17 = 0

x^2-10*x+17 = 0

DELTA = (-10)^2-(1*4*17)

DELTA = 32

DELTA > 0

x = (32^(1/2)+10)/(1*2) or x = (10-32^(1/2))/(1*2)

x = (4*2^(1/2)+10)/2 or x = (10-4*2^(1/2))/2

(x-((10-4*2^(1/2))/2))*(x-((4*2^(1/2)+10)/2)) = 0

1/4*(x-((10-4*2^(1/2))/2))*(x-((4*2^(1/2)+10)/2)) = 0

( x-((10-4*2^(1/2))/2) )

x-((10-4*2^(1/2))/2) = 0 // + (10-4*2^(1/2))/2

x = (10-4*2^(1/2))/2

( x-((4*2^(1/2)+10)/2) )

x-((4*2^(1/2)+10)/2) = 0 // + (4*2^(1/2)+10)/2

x = (4*2^(1/2)+10)/2

x in { (10-4*2^(1/2))/2, (4*2^(1/2)+10)/2 }

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